unordered_set example with inline lambda

Grzegorz Jabłoński
1 parent b30744b4
Showing 2 changed files with 31 additions and 2 deletions
examples09/07-closures/makefile
examples09/07-closures/unordered_set4.cpp
-all: fun1 fun2 fun3 fun4 fun5 unordered_set3
+all: fun1 fun2 fun3 fun4 fun5 unordered_set3 unordered_set4
  
 fun1: fun1.o
 	g++ -g -Wall $^ -o $@
@@ -37,7 +37,13 @@ unordered_set3.o: unordered_set3.cpp
 unordered_set3: unordered_set3.o
 	g++ -g -Wall $^ -o $@
  
+unordered_set4.o: unordered_set4.cpp
+	g++ -std=c++2a -g -c -Wall $< -o $@
+
+unordered_set4: unordered_set4.o
+	g++ -g -Wall $^ -o $@
+
 .PHONY: clean
  
 clean:
-	-rm fun1.o fun1 fun2.o fun2 fun3.o fun3 fun4.o fun4 fun5.o fun5 unordered_set3.o unordered_set3
 \ No newline at end of file
+	-rm fun1.o fun1 fun2.o fun2 fun3.o fun3 fun4.o fun4 fun5.o fun5 unordered_set3.o unordered_set3 unordered_set4.o unordered_set4
 \ No newline at end of file
+#include <functional>
+#include <unordered_set>
+using namespace std;
+#include "employee.h"
+
+int main() {
+  Employee Ben("Ben", "Keller", "000-00-0000");
+  Employee Bill("Bill", "McQuain", "111-11-1111");
+  Employee Dwight("Dwight", "Barnette", "888-88-8888");
+
+  unordered_set<Employee, decltype([](const Employee &o) {
+                  return std::hash<std::string>()(o.FirstName) ^
+                         (std::hash<std::string>()(o.LastName) << 1) ^
+                         (std::hash<std::string>()(o.ID) << 2);
+                })>
+      S;
+  S.insert(Bill);
+  S.insert(Dwight);
+  S.insert(Ben);
+
+  for (auto i : S)
+    cout << i << endl;
+}